3x^2-25x-500=0

Solution for 3x^2-25x-500=0 equation:

3x^2-25x-500=0

a = 3; b = -25; c = -500;
Δ = b2-4ac
Δ = -252-4·3·(-500)
Δ = 6625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6625}=\sqrt{25*265}=\sqrt{25}*\sqrt{265}=5\sqrt{265}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-5\sqrt{265}}{2*3}=\frac{25-5\sqrt{265}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+5\sqrt{265}}{2*3}=\frac{25+5\sqrt{265}}{6}
$